2p^2-20=-12p

Solution for 2p^2-20=-12p equation:

2p^2-20=-12p

We move all terms to the left:

2p^2-20-(-12p)=0

We get rid of parentheses

2p^2+12p-20=0

a = 2; b = 12; c = -20;
Δ = b2-4ac
Δ = 122-4·2·(-20)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{19}}{2*2}=\frac{-12-4\sqrt{19}}{4}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{19}}{2*2}=\frac{-12+4\sqrt{19}}{4}
$